DS = 3 RS.
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

Given: $P R ∥ B S$ , P is mid point of AB and Q is mid point of DR
$2 A D = A B$
$2 A D = A P + P B$
$2 A D = 2 A P$ (P is mid point of AB)
$A D = A P$
or A is mid point of PD
hence, $B D = 3 P B$
Now, In $△ A B S$ ,
$P R ∥ B S$ ,
By equal intercept theorem,
$\frac{B D}{B P} = \frac{D S}{R S}$
$3 = \frac{D S}{R S}$
$D S = 3 R S$

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