Dual behaviour of the matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnified images of biological molecules and other types of material. If the velocity of the electrons in this microscope is $1.6 \times 10^{6}$ $m s^{- 1}$ , calculate de Broglie wavelength associated with this electron.

325 pm

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455 pm

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474 pm

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526 pm

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Solution

The correct option is B 455 pm
Let us consider the problem:
Using de Broglie's equation
$λ = \frac{h}{m v} - - - - - 1$
putting values in equation 1 we have
$λ = \frac{6.626 \times 10^{- 34}}{(9.11 \times 10^{- 31}) (1.6 \times 10^{6})}$
Implies that
$= 4.55 \times 10^{- 10} m$
Hence the answer is $= 455 p m$

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Q. Dual behaviour of matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnified images of biological molecules and other type of material. If the velocity of the electron in this microscope is

1.6 \times 10^{6} {m s}^{- 1}

, calculate de Broglie wavelength associated with this electron.

Q. Electrons used in an electron microscope are accelerated by a voltage of

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Q. An electron microscope uses electrons accelerated by a voltage of 50 kV. Determine the de-Broglie wavelength associated with the electrons. Taking other factors, such as numerical aperture etc., to be same, how does the resolving power of an electron microscope compare with that of an optical microscope which used yellow light?

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kV. If the voltage is increased to

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An electron microscope uses electrons accelerated by a voltage of 50 kV. Determine the de Broglie wavelength associated with the electrons. If other factors (such as numerical aperture, etc.) are taken to be roughly the same, how does the resolving power of an electron microscope compare with that of an optical microscope which uses yellow light?

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The correct option is B 455 pmLet us consider the problem:Using de Broglie's equationλ=hmv−−−−−1putting values in equation 1 we haveλ=6.626×10−34(9.11×10−31)(1.6×106)Implies that= 4.55×10−10mHence the answer is = 455pm