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Standard XII

Physics

Time Period Independent of Amplitude

Due to a mass...

Question

Due to a mass distribution, the gravitational field is $\frac{k}{x^{3}}$ along x-axis where $k$ is a constant. If the gravitational potential is taken to be at infinity, then the gravitational potential at $x$ is

\frac{k}{x}

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\frac{k}{2 x^{2}}

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\frac{k}{x^{4}}

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\frac{k}{x^{6}}

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Solution

The correct option is B $\frac{k}{2 x^{2}}$
$V = - \int E d x = - \int \frac{K}{x^{3}} d x = K (\frac{1}{2 x^{2}}) = \frac{K}{{2 x}^{2}}$

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