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Question

Due to a point isotropic sound source, the sound level at a point is observed as 40 dB. The density of air is ρ = 1511kg/m3 and velocity of sound in air is 330 m/s. (The threshold intensity is 1012Wm2)

The pressure amplitude at the observation point is x(103)N/m2. Then x = _____


A

9

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B

6

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C

2

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D

3

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Solution

The correct option is D

3


In the propagation of sound waves, let pressure amplitude be Δp0 and displacement amplitude be A.

Δp0 = BAK where symbols have their usual meanings

From SL = 10log II0

40 = 10logI1012 I = 108W/m2

From I = Δp202 ρv

Δp0 = I×2ρv = 108×2×1511×330N/m2


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