CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Due to a point isotropic sound source, the sound level at a point is observed as 40 dB. The density of air is ρ = 1511kg/m3 and velocity of sound in air is 330 m/s. (The threshold intensity is 1012Wm2)

The pressure amplitude at the observation point is x(103)N/m2. Then x = _____


  1. 3

  2. 9

  3. 6

  4. 2


Solution

The correct option is A

3


In the propagation of sound waves, let pressure amplitude be Δp0 and displacement amplitude be A.

Δp0 = BAK where symbols have their usual meanings

From SL = 10log II0

40 = 10logI1012  I = 108W/m2

From I = Δp202 ρv

Δp0 = I×2ρv = 108×2×1511×330N/m2

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...



footer-image