Due to a small magnet, intensity at a distance x in the end on position is $9$ gauss. What will be the intensity at a distance $\frac{x}{2}$ on broad side on position.

9

gauss

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4

gauss

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36

gauss

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4.5

gauss

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Solution

The correct option is C $36$ gauss
B_axis = (2M / x³)
B_equator = (M/y³)
at distance x, B_axis = 9 Gauss
at distance y = (x/2)
B_equator = [M / (x/2)³] = (M / x³) × 8 = (8M / x³)
B_axis = (2M / x³) = 9 Gauss
(M/x³) = (9/2) Gauss
B_equator = 8 × (9/2) = 36 Gauss.

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Due to a small magnet, intensity at a distance x in the end on position is 9 gauss. What will be the intensity at a distance x2 on broad side on position.

The correct option is C 36 gaussBaxis = (2M / x3)Bequator = (M/y3)at distance x, Baxis = 9 Gaussat distance y = (x/2)Bequator = [M / (x/2)3] = (M / x3) × 8 = (8M / x3)Baxis = (2M / x3) = 9 Gauss(M/x3) = (9/2) Gauss Bequator = 8 × (9/2) = 36 Gauss.

Due to a small magnet, intensity at a distance x in the end on position is $9$ gauss. What will be the intensity at a distance $\frac{x}{2}$ on broad side on position.

The correct option is C $36$ gauss
B_axis = (2M / x³)
B_equator = (M/y³)
at distance x, B_axis = 9 Gauss
at distance y = (x/2)
B_equator = [M / (x/2)³] = (M / x³) × 8 = (8M / x³)
B_axis = (2M / x³) = 9 Gauss
(M/x³) = (9/2) Gauss
B_equator = 8 × (9/2) = 36 Gauss.