Due to air a falling body faces a resistive force proportional to square of velocity v, consequently its effective downward acceleration is reduced and is given by a=g−kv2 where k=0.002m−1. The terminal velocity of the falling body is (in m/s)
A
60
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B
70
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C
80
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D
90
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Solution
The correct option is B70 As velocity increases a will decrease and at some point, it will become zero and velocity become constant that is terminal velocity.
At terminal velocity- g−kv2ter=0⟹v2ter=gk=9.80.002=4900⟹vter=70ms