Due to an impulse, the change in momentum of a body is $1.8 k g m s^{- 1}$ . How much is the force acted on it if the duration of the force acting is $0.2 s$ ?

$9 N$

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$3.6 N$

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$0.36 N$

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$6 N$

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Solution

The correct option is A
$9 N$

Given that, change in momentum, $△ (m v) = 1.8 k g m s^{- 1}$
Duration of the force acting, $t = 0.2 s e c$
We know that:
Impulse =Change in momentum = $F \times t$
$△ (m v) = F \times t$
$F = \frac{△ (m v)}{t} = \frac{1.8}{0.2}$
$\Rightarrow$ $F = 9 N$

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Due to an impulse, the change in momentum of a body is 1.8 kg ms−1. How much is the force acted on it if the duration of the force acting is 0.2 s ?

The correct option is A 9 N Given that, change in momentum,△(mv)=1.8 kg ms−1 Duration of the force acting, t=0.2 sec We know that: Impulse =Change in momentum =F×t △(mv)=F×t F=△(mv)t=1.80.2 ⇒ F=9N

Due to an impulse, the change in momentum of a body is $1.8 k g m s^{- 1}$ . How much is the force acted on it if the duration of the force acting is $0.2 s$ ?

The correct option is A
$9 N$

Given that, change in momentum, $△ (m v) = 1.8 k g m s^{- 1}$
Duration of the force acting, $t = 0.2 s e c$
We know that:
Impulse =Change in momentum = $F \times t$
$△ (m v) = F \times t$
$F = \frac{△ (m v)}{t} = \frac{1.8}{0.2}$
$\Rightarrow$ $F = 9 N$