You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Forced Oscillations

Due to some f...

Question

Due to some force $F_{1}$ a body oscillates with period ( $4 / 5$ ) $s$ and the due to other force $F_{2}$ it oscillates with period $3 / 5 s$ . if both the forces acts simultaneously new period will be

0.72 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.64 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.48 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.36 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.48 s$
$F = \frac{4 π^{2} m x}{T^{2}}$
$F_{1} = \frac{4 π^{2} m x}{T^{2}}$
$F_{2} = \frac{4 π^{2} m x}{T_{2}^{2}}$
$F_{1} + F_{2} = \frac{4 π m x}{T^{2}}$
$∴ \frac{1}{T^{2}} = \frac{1}{T_{1}^{2}} + \frac{1}{T_{2}^{2}}$
$\frac{1}{T^{2}} = (\frac{5}{4})^{2} + (\frac{5}{3})^{2}$
$T = 0.48$

Suggest Corrections

Similar questions

Due to some force $F_{1}$ a body oscillates with period 4/5 sec and due to other force $F_{2}$ oscillates with period 3/5 sec. If both forces act simultaneously, the new period will be

Q. Due to some force

F_{1}

, a body oscillates with period

\frac{4}{5} sec

, and due to other force

F_{2}

, oscillates with period

\frac{3}{5} sec

. If both forces act simultaneously, the new period will be :

Q. Due to some force

F_{1}

, a body oscillates with period 4/5 second and due to other force

F_{2}

it oscillates with the period of 3/5 sec. If both forces act simultaneously new period will be

Q. A box executes simple harmonic motion under the action of a force

F_{1}

with a time period

\frac{4}{5} s

. If the force is changed to

F_{2}

, it executes S.H.M with time period

\frac{3}{5} s

. If both the forces

F_{1}

and

F_{2}

act simultaneously in the same direction on the body, its time period in seconds will be

Q. A body executes simple harmonic motion under the action of a force

F_{1}

with a time period

(4 / 5)

seconds. If the force is changed to

F_{2}

, it executes SHM with time period

(3 / 5)

seconds. If both the forces

F_{1}

and

F_{2}

act simultaneously in the same direction on the body, its time period (in seconds) is

Join BYJU'S Learning Program

Due to some force F1 a body oscillates with period (4/5) s and the due to other force F2 it oscillates with period 3/5s. if both the forces acts simultaneously new period will be

The correct option is C 0.48sF=4π2mxT2F1=4π2mxT2F2=4π2mxT22F1+F2=4πmxT2∴1T2=1T21+1T221T2=(54)2+(53)2T=0.48

Due to some force $F_{1}$ a body oscillates with period ( $4 / 5$ ) $s$ and the due to other force $F_{2}$ it oscillates with period $3 / 5 s$ . if both the forces acts simultaneously new period will be