Question

During a ${\beta }^{-}$ decay which of the following statements are correct?

• A. The daughter nucleus has one proton less than the parent nucleus
• B. The daughter nucleus has one proton more than the parent nucleus
• C. An electron which is already present within the nucleus is rejected
• D. A neutron in the nucleus decays emitting an electron

Answer 1

The correct option is B The daughter nucleus has one proton more than the parent nucleus

${\beta }^{-}Decay$

${}_{-1}^{\theta }e$ or ${}_{-1}^o\beta \to$ Symbols for Beta particles emitted during ${\beta }^{-}$ decay.

$\theta \to$ electron is emitted

Eg- ${}_{53}^{131}I{\to }_{54}^{131}Xe{+}_{-1}^0\beta +\overline{{\upsilon }_e}$

where, ${}_{-1}^0\beta$ is $\beta$ particle

$\overline{{\upsilon }_e}$ is antineutrino

So, $\left(B\right)$ is correct option.