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Question

During a cyclic thermodynamic process, a gas absorbs 45 J of heat.
Which table correctly describes the change in internal energy in the gas and work done by the gas during this cycle?

A
45 J
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B
54 J
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C
40 J
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D
50 J
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E
60 J
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Solution

The correct option is A 45 J
As heat is absorbed by the gas, Q=+45 J
Change in internal energy of the gas during one cycle is zero i.e ΔU=0 J
From 1st law of thermodynamics : Q=ΔU+W
45=0+W W=+45 J
Thus the work done by the gas is 45 J.

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