Question

During a festive season a sweet seller prepared 420laddus 120barfis 180 kaju katlis .he wanted to distribute equally in the boxes find the greatest number of sweet that can be kept in a box

Answer 1

this is to find the hcf of the number of different sweets
so Number of laddus=420
Number of Barfis=120
Number of Kaju KAttis=180

HCF of 420,120,180 = 60

SO 60 boxes can be used.

SO in each box ,
420/60=7 Laddus
120/60=2 barfis
180/60=3 Kaju Kattis
will be pesent

Like if satisfied