During a laboratory experiment, a $19.6 N$ pile driver is dropped $2$ m on to the head of a nail, which is driven $2.45 c m$ into a wood board. The frictional force exerted by the wood on the nail is

96.04 N

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165 N

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1600 N

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1960 N

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3200 N

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Solution

The correct option is C $1600 N$
From work-energy theorem, the amount of gravitational potential energy lost by the pile-driver is the work done by it against the force of friction,
Hence $m g h = f . s$

$⟹ f = \frac{m g h}{s} = \frac{19.6 N \times 2 m}{0.0245 m} = 1600 N$ .

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During a laboratory experiment, a 19.6N pile driver is dropped 2 m on to the head of a nail, which is driven 2.45 cm into a wood board. The frictional force exerted by the wood on the nail is

The correct option is C 1600NFrom work-energy theorem, the amount of gravitational potential energy lost by the pile-driver is the work done by it against the force of friction,Hence mgh=f.s⟹f=mghs=19.6N×2m0.0245m=1600N.

During a laboratory experiment, a $19.6 N$ pile driver is dropped $2$ m on to the head of a nail, which is driven $2.45 c m$ into a wood board. The frictional force exerted by the wood on the nail is

The correct option is C $1600 N$
From work-energy theorem, the amount of gravitational potential energy lost by the pile-driver is the work done by it against the force of friction,
Hence $m g h = f . s$

$⟹ f = \frac{m g h}{s} = \frac{19.6 N \times 2 m}{0.0245 m} = 1600 N$ .