During a tennis match, a player serves at 23.6ms−1, the ball leaving the racquet horizontally 2.37m above the court surface. By how much does the ball clear the net which is 12m away and 0.9m high? (answer in metres)
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Solution
Let t be the time taken by the ball to clear the net. Horizontal distance between the racquet and the net =12m ⇒12=uxt=23.6×t
Height by which ball will fall in time t is y=12gt2=12×10×(1223.6)2=1.3m
Let h be the height above the net at which at the ball will pass it. Then, 2.37=y+h+0.9 ∴h=2.37−0.9−1.3=0.17 m