During a tennis match, a player serves at 23.6ms−1, the ball leaving the racquet horizontally 2.37m above the court surface. By how much does the ball clear the net which is 12m away and 0.9m high? (Take g=10m/s2)
A
0.17m
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B
2.2m
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C
1.3m
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D
0.9m
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Solution
The correct option is A0.17m Let t be the time taken by the ball to clear the net. Horizontal distance between the racquet and the net =12m ⇒12=uxt=23.6×t Height by which ball will fall in time t is y=12gt2=12×10×(1223.6)2=1.3m Let h be the height above the net at which at the ball will pass it. Then, 2.37=y+h+0.9 ∴h=2.37−0.9−1.3=0.17 m