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Question

During a tennis match, a player serves at 23.6 ms1, the ball leaving the racquet horizontally 2.37 m above the court surface. By how much does the ball clear the net which is 12 m away and 0.9 m high?
(Take g=10 m/s2)

A
0.17 m
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B
2.2 m
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C
1.3 m
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D
0.9 m
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Solution

The correct option is A 0.17 m
Let t be the time taken by the ball to clear the net.
Horizontal distance between the racquet and the net =12 m
12=uxt=23.6×t
Height by which ball will fall in time t is
y=12gt2=12×10×(1223.6)2=1.3 m
Let h be the height above the net at which at the ball will pass it.
Then, 2.37=y+h+0.9
h=2.370.91.3=0.17 m

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