During absorption of $H_{2} O$ by roots, the $H_{2} O$ potential of cell sap is lower than that of:

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That of pure

H_{2} O

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One

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Solution

The correct option is B That of pure $H_{2} O$
During absorption of H2O by roots, the H2O potential of cell sap is lower than that of that of pure H2O. During absorption of water by roots the water potential of cell sap is lower than that of pure water. Due to higher osmotic pressure of water in the root hair, the water from soil passes into the root hair.

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H_{2} O

H - F

H_{2} O [∵ E N o f F > O & H b o n d \propto E N]

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V^{2 +} + V O^{2 +} + 2 H^{+} \to 2 V^{3 +} + H_{2} O; E^{o} = 0.616 V

V^{3 +} + A g^{+} + H_{2} O \to V O^{2 +} + 2 H^{+} + A g; E^{o} = 0.439 V

E_{V^{3 +} / V^{2 +}}^{o}

E_{A g^{+} / A g}^{o} = 0.799 V

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