During adsorption which of the following is positive?

Δ G

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T Δ S

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Δ G + T Δ S

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none of these

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Solution

The correct option is D none of these
$△ G = △ H + T △ S$

For adorption to be spontaneous, $△ G$ must be negative. $△ H$ has a significantly high negative value as $T △ S$ is positive.

Hence, none of these is the correct option.

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Similar questions

Δ H

Δ S

Δ G

Δ G = Δ H - T Δ S

Δ G > 0

Δ_{t o t a l} S < 0

T Δ S > 0

Δ G < 0

$Δ G = Δ H - T Δ S$ and $Δ G = Δ H + T {[\frac{d (Δ G)}{d T}]}_{p}$ , then $(\frac{d E_{c e l l}}{d T})$ is:

T Δ S

Δ G = Δ H - T Δ S

Δ G = Δ H - T Δ S

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