During an adiabatic process an object does 100J of work and its temperature decreases by 5K. During another process it does 25J of work and its temperature decreases by 5K. Its heat capacity for 2nd process is
A
20J/K
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B
24J/K
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C
15J/K
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D
100J/K
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Solution
The correct option is D15J/K For adiabatic process, dU=−100J which remains same for other processes also. Let C be the heat capacity of 2nd process then −(C)5=dU+dW =−100+25=−75 ∴C=15J/K