During an analysis of 255 mg of a molecule that contains only C, H and O, 561 mg CO2 is produced along with 306 mg H2O on combustion. If the molar mass of the compound is 180 g/mol, what is the molecular formula of the compound ?
(molar mass of compound =180 g/mol and n =integer)
n=molecular massempirical mass=18060=3
so we get n=3
molecular formula n=n×empirical formula=3×C3H8O
so, Molecular formula =C9H24O3