During an experiment with a meter bridge, the galvanometer shows a null point when the jockey is pressed at 40.0 cm using a standard resistance of 90Ω. The least count of the scale used in the meter bridge is 1mm. The unknown resistance is
A
\((60 \pm 0.15) \Omega\)
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B
\((135 \pm 0.05) \Omega\)
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C
\((60 \pm 0.25) \Omega\)
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D
\((135 \pm 0.23) \Omega\)
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Solution
The correct option is C \((60 \pm 0.25) \Omega\) We have, X=Sl1l2 where l1=40±0.1cm=40±0.25% l1=60±0.1cm=60±0.16% Δxx=Δl1l1+Δl2l2 =0.25+0.16 =0.41% Xm=90×4060 60cm ∴=X=60±0.41% =60±0.25)Ω