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Question

During β decay of stationary nucleus, an electron is observed with a KE of 1.0 MeV. From this what can be concluded about Q value of the decay?


  1. It can be greater than 1MeV

  2. All the above

  3. It can be equal to 1MeV

  4. It can be less than 1MeV


Solution

The correct option is B

All the above


In β decay the energy released is in the form of KE if electron & the energy shared by antineutrino. The energy of antineutrino can be anything from 0 to a finite value.

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