Question

During ${\beta }^{-}$ decay, a neutron inside nucleus converts into proton, electron and $x$. Then, what is the particle $x$?

• A. ${\pi }^{+}$- meson
• B. neutrons
• C. anti-neutrino
• D. ${\pi }^{-}$- meson

Answer 1

The correct option is C anti-neutrino

Process of $\beta$ decay
$n^0{\to }_{1}P+e^{-}+\overline{V}e$
where, $p=proton$
$e^{-}=electron$
$\overline{V}e=antineutrino$