During compression of a spring the work done is 10kJ and 2kJ escaped to the surroundings as heat. The change in internal energy, ΔU (in kJ) is:
A
8
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B
−12
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C
12
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D
−8
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Solution
The correct option is A8 In the given system, during the compression of a spring the workdone is 10kJ and 2kJ of heat is escaped to the surroundings. So, q=−2kJ and W=10kJ. According to the first law of thermodynamics, ΔU=q+W=−2kJ+10kJ ΔU=8kJ.
The change in internal energy, ΔU=8kJ.