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Representation of Cell

During electr...

Question

During electrochemical process, when 2 rods, Zn and Cu are taken in seperate containers why does Zn releases 2 electrons and Cu accepts it and NOT vice versa?

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Solution

Zinc is more reactive than copper. It is placed above copper in electrochemical series. So, Zn is more oxidizing than Cu. So, Zn will act as anode and undergo oxidation and Cu act as cathode and will undergo reduction.

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Similar questions

In an electrochemical cell represented as,

Zn | Zn²⁺₍c₁₎ || Cu²⁺₍c₂₎| Cu

So in this cell,

a.Zn is oxidized

b.Zn is reduced

c.Cu is oxidized

d.Cu is reduced

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

E^{o}

C u

Z n

0.35

- 0.76

Z n^{2 +}

C u^{2 +}

Z n {S O}_{4}

C u {S O}_{4}

Z n

C u

K C l

Z n > C u

Below given are emf of three galvanic cells, represented by $E_{1}$ , $E_{2}$ and $E_{3}$ . Which of the following is true?

I. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u$

II. $Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (1 M) | C u$

III. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (0.1 M) | C u$

E^{\circ}

Z n (s) | Z n^{2 +} 1 M (a q .) ∥ C u^{2 +} 1 M (a q .) | C u (s)

1.10 V

25^{\circ} C

Z n (s) + C u^{2 +} (a q .) ⇌ Z n^{2 +} (a q .) + C u (s)

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