During electrolysis of a salt solution 0.05F of electricity deposits 1.6g of divalent metal. Theatomic wt. of the metal is:
A
32
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B
16
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C
64
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D
1.6
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Solution
The correct option is C 64 1 F of charge displaces E g of ion. Where E is the equivalent wt of the ion. But 0.05 F of charge displaces 1.6 g of metal. Hence 0.05E=1.6gE=1.60.05g=32g It is a divalent metal. Hence, Atomic weight=E×2=32g×2=64g.