During electrolysis of an aqueous of sulphuric acid between platinum electrodes, two types of anions migrate towards the anode but only one of them is discharged.
Name the main product of the discharge of anion at the anode and write the anode reaction.

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Solution

Reactions in electrolysis of sulphuric acid:

$H_{2} S O_{4} \to 2 H^{+} + {S O_{4}}^{- 2}$
$H_{2} O \to H^{+} + O H^{-}$

$O H^{-}$ having higher reduction potential gets reduced faster than ${S O_{4}}^{- 2}$

Reaction is:
$O H^{-} \to O H + e^{-}$
$4 O H \to 2 H_{2} O + O_{2}$

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An electrolytic cell is set up using two platinum electrodes and an aqueous solution of copper (II) sulphate given below:

Name the ion discharged at the anode.

N a_{2} S O_{4}

(P t)

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