Question

During electrolysis of $H_{2}O$, molar ratio of $H_2$ and $O_2$ produced is:

• A. $2:1$
• B. $1:2$
• C. $1:1$
• D. $1:4$

Answer 1

The correct option is A $2:1$

$H_{2}O\stackrel{Electrolysis}{\to }{H}_2+\frac{1}{2}{O}_2$

$\therefore$ Ratio $\Rightarrow 1:\frac{1}{2}$

$\Rightarrow 2:1$.

Hence, option $A$ is correct.