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Standard IX

Chemistry

Electrochemcial Reaction

During electr...

Question

During electrolysis of H2SO4 (aq) with high charge density, H2S2O8 is formed as by product . In such electrolysis , 44.8L H2 ( g) and 15L O2 ( g) liberated at STP.Hence ,the moles of H2S2O8 formed is approximately equal to .

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Q. Peroxydisulfuric acid

(H_{2} S_{2} O_{8})

can be prepared by electrolytic oxidation of

H_{2} S O_{4}

as:

2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{+} + 2 e

O_{2}

and

H_{2}

are by products. In such on electrolysis

0.87

g of

H_{2}

and

3.36

O_{2}

were generated at STP. Report the mass of

H_{2} S_{2} O_{8}

formed in decagram (write nearest integer).

Q. Marshall's acid or perdisulphuric acid

(H_{2} S_{2} O_{8})

can be prepared by electrolytic oxidation of

H_{2} S O_{4}

as :

2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{\oplus} + 2 e^{-}

O_{2}

and

H_{2}

are byproducts. In such an electrolysis 9.72 L of

H_{2}

and 2.35 L of

O_{2}

were produced at S.T.P. What is the weight of

H_{2} S_{2} O_{8}

formed ?

Q. During an electrolysis of conc.

H_{2} S O_{4}

, perdisulphuric acid

(H_{2} S_{2} O_{8})

and

O_{2}

form in equimolar amount. The amount of

H_{2}

that will form simultaneously will be:

(2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{+} + 2 e^{-})

Marshalls acid is prepared by the electrolytic oxidation of $H_{2} S O_{4}$ as $2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{\oplus} + 2 e^{-}$

Oxygen and hydrogen are byproducts. In such Electrolysis 2.24 L of $H_{2}$ amd 0.56 L $O_{2}$ were produced at STP. The weight of $H_{2} S_{2} O_{8}$ formed is:

Q. One of the methods of preparation of per disulphuric acid,

H_{2} S_{2} O_{8}

involve electrolytic oxidation of

H_{2} S O_{4}

at anode

(2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{+} + 2 e^{-})

with oxygen and hydrogen as by-products. In such an electrolysis,

10.08 L of H_{2}

and 2.24 L of

O_{2}

were generated at STP. What is the weight of

H_{2} S_{2} O_{8}

formed?

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