Question

During glycolysis, the conversion of one mole of $3PGA$ to $C_3{H}_4{O}_3$ yield 2 moles of ATP. But the oxidation of glucose to $C_3{H}_4{O}_3$ produces a total of 4 moles of ATP. Where do the remaining 2 moles of ATP come from?

• A. One mole of glucose gives 2 moles of $3PGA$
• B. Glycolysis produces $2NADH$
• C. Fermentation of $C_3{H}_4{O}_3$ produces $2ATP$ more
• D. $2ATP$ are used in the conversion of glucose to $3PGA$

Answer 1

The correct option is A One mole of glucose gives 2 moles of $3PGA$

Two moles of ATP are produced when one mole of glyceraldehyde-3-phosphate or 3PGA is converted to pyruvic acid ($C_3{H}_4{O}_3$) . Glyceraldehyde-3-phosphate is produced from glucose in the first phase of glycolysis. Each mole of glucose produces 2 moles of glyceraldehyde-3-phosphate. Therefore, two moles of 3PGA when converted to pyruvic acid, yield 4 moles of ATP.