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Question

During grinding of a C.I specimen of 10 mm wide and 100 mm long with A 27 K 6V grinding wheel of 300 mm dia and 25 mm wide, the wheel has undergone a radial wheel wear of 50 microns after removing a layer of 5 mm. The grinding ratio is

A
21.2
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B
2.12
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C
42.4
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D
4.24
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Solution

The correct option is D 4.24
Volume of grinding wheel wear
=π4(D2InitialD2Final)=π4((300)2(300100×103)2)=π4(3002299.92)×25=1177.9 mm3
Volume of material removal of workpiece
=l×w×d=10×100×5=5000 mm3Grinding ratio=1177.9/5000=4.24

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