Question

During illness an 80 Kg man ran n forever of ${102.2}^{o}F$ instead of normal body temperature of ${98.6}^{o}F$. Assuming that human body is mostly water,how much heat is required to raise his temperature by that amount

• A. 100 kcal
• B. 160 kcal
• C. 50 kcal
• D. 92 kcal

Answer 1

Answer: (B)

160 kcal

Converting Farenhite to celsius:

${102.2}^{\circ }F\to {39}^{\circ }C$ and ${98.6}^{\circ }F\to {39}^{\circ }C$

Hence $\Delta Q=m.s.\Delta Q=80\times 1000\times (39-37)$

$Q=16\times {10}^{4}cal=160kcal.$