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Question

During isothermal expansion of two moles of an ideal gas from 20 atm to 4 atm at 373 K, the work done is:

A
–2.4 kcal
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B
3.8 kcal
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C
2.4 kcal
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D
–10.5 kcal
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Solution

The correct option is A –2.4 kcal
Work done in a reversible isothermal process of gas (w) = 2.303×nRT logP1P2

where, n is the number of moles,
R is the gas constant (2 cal/mol.K)
T is temperature and
P1 and P2 are the initial and final pressure of the gas.

According to the given conditions,
w=2.303×2×2×373 log204
=2401.7 cal
or 2.4 kcal

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