Question

During machining, the wear land $\left(h\right)$ has been plotted against machining time $T$ as given in the following figure



For a critical wear land to $1.8mm$ the cutting tool life (in $min$) is

• A. $52.00$
• B. $51.67$
• C. $51.50$
• D. $50.00$

Answer 1

The correct option is B $51.67$

$\text{Slope}=\frac{2.0-0.8}{60-10}=0.024$

$\text{If wear land}=1.8mm$

$\text{Tool life:}$
$T=10+\frac{1.8-0.8}{0.024}$

$=51.67min$