Question

During MIG welding operation, the electrode diameter used is 2 mm, wire feed rate is 3 m/min, total area of weld bead is 31.4 mm${}^2$. Then the welding speed (mm/sec) used in the welding process will be _______.

• A. 0
• B. 5
• C. 10
• D. 15

Answer 1

The correct option is B 5

Melting rate of electrode

$\frac{\pi }{4}\times 2^2\times 3000=9420m{m}^3/min$

Melting rate of electrode = filling rate of weld bead

$\text{9420 = area of weld}\times \text{velocity of welding}$

$\text{9420 = 31.4}\times \text{V}$

$\Rightarrow \text{V = 9420/31.4 = 300 mm/min}$

$\text{Welding speed (mm/sec) =}\frac{300}{600}\text{= 5 mm/sec}$