During morning assembly at a school, $35$ rows of students are formed. If the strength of the school is $1680,$ calculate how many students are there in each row? (Assume each row has an equal number of students.)

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Solution

Total number of students in the school $= 1680 .$
Numbers of rows formed during morning assembly at a school $= 35$
By assuming each row has an equal number of students.
$∴$ Number of in each row $= 1680 \div 35$
$= 48$
$3548 1680 - 140 - - - - - - 0280 - 280 - - - - - 000$
Hence, the number of students in each row is $48 .$

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During morning assembly at a school, 35 rows of students are formed. If the strength of the school is 1680, calculate how many students are there in each row? (Assume each row has an equal number of students.)

Total number of students in the school =1680.Numbers of rows formed during morning assembly at a school =35By assuming each row has an equal number of students. ∴ Number of in each row =1680÷35 =4835481680-140------0280-280-----000Hence, the number of students in each row is 48.

During morning assembly at a school, $35$ rows of students are formed. If the strength of the school is $1680,$ calculate how many students are there in each row? (Assume each row has an equal number of students.)