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Question

During orthogonal metal cutting process, the following data is obtained:
Rake angle = 12°
Chip thickness ratio = 0.5
Undeformed thickness = 0.7 mm
Cutting speed = 2.4 m/s
If the mean thickness of primary shear zone is 25 microns, then shear strain rate (in s1) during the process is

A
4.9 × 104
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B
0.98 × 104
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C
9.8 × 104
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D
0.49 × 104
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Solution

The correct option is C 9.8 × 104

r=0.5;α=12;v=2.4m/s

Now, tanϕ=rcosα1rsinα=0.5cos1210.5sin12

ϕ=tan1(0.5458)=28.63

Also, shear velocity is,

vs=vcosαcos(ϕα)=2.4cos12cos(28.6312)=2.45m/s

Shear strain rate=vsts=2.4525×106=9.8×104s1


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