During the change of $O_{2}$ to $O_{2}^{-}$ , the incoming electron goes to the orbital:

σ^{*} 2 p_{z}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π 2 p_{y}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π^{*} 2 p_{x}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

π 2 p_{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $π^{} 2 p_{x}$
Solution:- (C) $π^{} 2 p_{x}$

Molecular orbital diagram of $O_{2}$ molecules is shown in the figure.

An incoming electron will go in $π^{*} 2 p_{x}$ orbital since it is a half-filled orbital.

Suggest Corrections

Similar questions

O_{2}

O_{2}^{-}

σ_{2 S}

L i_{2}

σ^{*} 1 s, σ^{*} 2 s, σ 1 s, π 2 p_{y}, π^{*} 2 p_{x}, π^{*} 2 p_{z}, π 2 p_{z}

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

Correct sequence of energy levels in N $_{2}$ molecule

O_{2}^{+}

O_{2}

Join BYJU'S Learning Program