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Question

During the discharge of a lead storage battery, the density of sulphuric acid fell from 1.294 to 1.139 g ml1 and sulphuric acid of the density of 1.294 g ml1 is 39% by mass and that of the density of 1.139 g ml1 is 20% by mass. The battery holds 3.5 litre of acid and the volume practically remained constant during the discharge. Calculate the no. of ampere hour for which the battery must have been used. The charging and discharging reactions are:


Pb+SO24PbSO4+2e charging
PbO2+4H++SO24+2ePbSO4+2H2O discharging

A
2.5A
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B
1.7A
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C
3.2A
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D
None of these
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Solution

The correct option is D None of these
Initial mass of H2SO4=1.294×39100×3.5=1766 gm

Final mass of H2SO4=1.139×20100×3.5=797 gm

Mass of H2SO4 electrolyzed=(1766797)980 gm

96500 C charge electrolyzes 49 gm of H2SO4

980 gm H2SO4 is electrolysed by 96500×98049 C charge

Ampere hours required 96500×98049×60×60=536 C/hr

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