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Types of Redox Reactions

During the di...

Question

During the disproportionation of iodine to iodide and iodate ions, the ratio of iodate and iodide ions formed in alkaline medium is:

A

1 : 5

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B

5 : 1

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C

3 : 1

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D

1 : 3

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Solution

The correct option is A 1 : 5
$3 I_{2} + O H^{-} ⟶ I O_{3}^{-} + 5 I^{-}$
$3$ $1$ $:$ $5$
Ratio of iodate to iodide ions $= 1 : 5$

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