CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

During the disproportionation of iodine to iodide and iodate ions, the ratio of iodate and iodide ions formed in alkaline medium is:


A
1 : 5
loader
B
5 : 1
loader
C
3 : 1
loader
D
1 : 3
loader

Solution

The correct option is A 1 : 5

$$3I_2+OH^-\longrightarrow IO^-_3+5I^-$$

$$3$$                            $$1$$      $$:$$       $$5$$

Ratio of iodate to iodide ions $$=1:5$$           


Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image