Question

During the electrolysis of acidified water with platinum electrodes, $H_2$ and $O_2$ are liberated at :

• A. cathode and anode respectively
• B. anode and cathode respectively
• C. cathode
• D. anode

Answer 1

The correct option is A cathode and anode respectively

During electrolysis of water,
At anode:
$2H_{2}O\to O_2+4H^{+}+4e^{-}$
At cathode:
$4H_{2}O+4e^{-}\to 2H_2+4O{H}^{-}$