During the electrolysis of copper (Ⅱ) sulphate solution using platinum as cathode and carbon as anode “Write the reactions at the cathode and at the anode”.

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Solution

Reaction at cathode and anode are as follows,
Reaction at the cathode:
$C u^{2 +} + 2 e^{-} \to C u$
Reaction at the anode:
$40 H^{-} - 4 e^{-} \to 2 H_{2} O + O_{2}$

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Q. During the electrolysis of copper (II) sulphate solution using platinum as cathode and carbon as anode:
(i) What do you observe at the cathode and at the anode?
(ii) What change is noticed in the electrolyte?
(iii) Write the reactions at the cathode and at the anode.

(a) Give reason: The electrolysis of acidulated water is considered to be an example of catalysis.

(b) During the electrolysis of copper [II] sulphate solution using platinum as cathode and carbon as anode

(i) State what you observe at the cathode and at the anode

(ii) State the change noticed in the electrolyte

(iii) Write the reactions at the cathode and at the anode.

Q. During the electrolysis of copper [II] sulphate solution using platinum as cathode & carbon as anode, the reactions at the cathode is :

Q. During the electrolysis of copper (Ⅱ) sulphate solution using platinum as cathode and carbon as anode “State the change noticed in the electrolyte”.

Describe what you would see at anode and cathode during electrolysis of copper (II) chloride, using platinum cathode and carbon anode. Write ionic equations for the reactions at anode and cathode.

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Factors Affecting Electrolysis

Standard X Chemistry

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During the electrolysis of copper (Ⅱ) sulphate solution using platinum as cathode and carbon as anode​ “Write the reactions at the cathode and at the anode”.

Reaction at cathode and anode are as follows, Reaction at the cathode: Cu2++2e−→Cu Reaction at the anode: 40H−−4e−→2H2O+O2

During the electrolysis of copper (Ⅱ) sulphate solution using platinum as cathode and carbon as anode “Write the reactions at the cathode and at the anode”.

Reaction at cathode and anode are as follows,
Reaction at the cathode:
$C u^{2 +} + 2 e^{-} \to C u$
Reaction at the anode:
$40 H^{-} - 4 e^{-} \to 2 H_{2} O + O_{2}$