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Question
During the electrolysis process 4 A electric current flows through a copper sulphate solution for 5 mins. Determine the number of copper atoms deposited at the cathode.
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Solution
Dear student,
Q = I t
= 4 x 5 x 60 =1200 C
Cu+2 + 2 e` > Cu
No. of Cu atoms deposited = 1200/ 2 x 1.602 x 10^-19 = 3.745 x 1021 atoms
Regards
Q = I t
= 4 x 5 x 60 =1200 C
Cu+2 + 2 e` > Cu
No. of Cu atoms deposited = 1200/ 2 x 1.602 x 10^-19 = 3.745 x 1021 atoms
RegardsSuggest Corrections
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