During the estimation of phosphorous present in an organic compound, which formula is used?

% of P

= \frac{66 \times Wt. of M g_{2} P_{2} O_{7} formed}{222 \times Wt. of the compound} \times 100

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% of P

= \frac{666 \times Wt. of M g_{2} P_{2} O_{7} formed}{22 \times Wt. of the compound} \times 100

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% of P

= \frac{222 \times Wt. of M g_{2} P_{2} O_{7} formed}{66 \times Wt. of the compound} \times 100

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% of P

= \frac{22 \times Wt. of M g_{2} P_{2} O_{7} formed}{666 \times Wt. of the compound} \times 100

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Solution

The correct option is A % of P $= \frac{66 \times Wt. of M g_{2} P_{2} O_{7} formed}{222 \times Wt. of the compound} \times 100$
During the estimation of phosphorous present in an organic compound, the formula used is % of P $= \frac{66 \times Wt. of M g_{2} P_{2} O_{7} formed}{222 \times Wt. of the compound} \times 100$

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