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Question

During the experiment you are given 2.5 m acetone solution in heptane (molar mass = 100 g/mol) having a density of 0.5 g/mL. Find the mole fraction of solute.

A
0.3
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B
0.2
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C
0.85
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D
0.02
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Solution

The correct option is B 0.2
Let us assume the weight of the solvent as 1 kg or 1000 g.
Molality (m)=Moles of solute Weight of solvent (kg)
Moles of acetone (solute) = 2.5 moles
Moles of solvent (heptane)=1000100=10 mol
Mole fraction of solute=Moles of soluteTotal moles=2.5(2.5+10)=2.512.5=0.2

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