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Question

# During the first 18 min of a 60 min trip, a car has an average speed of 11 ms−1. What should be the average speed for remaining 42 min so that car is having an average speed of 21 ms−1 for the entire trip?

A
25.3ms1
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B
29.2ms1
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C
31ms1
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D
35.6ms1
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Solution

## The correct option is A 25.3ms−1Distance covered in first 18 min = 11×18×60=11880mLet average speed for remaining trip be 'v'.Thus distance covered in remaining time = v×42×60=2520vmThus total distance, D=11880+2520vtotal time, T=60min=3600secThus Avg.Speed=21=DT(11880+2520v)=21×3600v≈25.3m/s

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