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B
electrons diffuse from p−side to n−side (p→n)
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C
electrons diffuse from n−side to p−side (n→p)
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D
holes diffuse from n−side to p−side (n→p)
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Solution
The correct options are A holes diffuse from p−side to n−side (p→n) C electrons diffuse from n−side to p−side (n→p) When a p-n junction is formed, i.e. p-type semiconductor is in contact with the n-type semiconductor, the concentration of holes is higher on p-side than on n-side of p-n junction whereas the concentration of electrons is higher on n-side than on p-side of the junction. As a result, holes will diffuse from p-side to n-side through junction and electrons will diffuse from n-side to p-side through the junction.