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# During the medical check-up of 35 students of a class, their weights were recorded as follows: Weight (in kg)Number of studentsLess than 38Less than 40Less than 42Less than 44Less than 46Less than 48Less than 50Less than 52035914283235Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.

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## Let us now plot the points corresponding to the ordered pairs given by (38,0),(40,3),(42,5),(44,9),(46,14),(48,28),(50,32) and (52,35) on a graph paper and join them by a free hand smooth curve.Now, Weight (in kg) Number of students (Frequency) 0−38 0 38−40 3−0=3 40−42 5−3=2 42−44 9−5=4 44−46 14−9=5 46−48 28−14=14 48−50 32−28=4 50−52 35−32=3Mode: The class which have highest frequency.In this case, class interval 46−48 is the modal class.Now,Lower limit of modal class, l=46,h=2,f1,=14,f0=5,f2=4We know that,Mode =l+(f1−f02f1−f0−f2)×h=46+(14−52(14)−5−4)×2=46+919×2=46+0.95Mode =46.95, verified.   Suggest Corrections  1      Similar questions
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