During the preparation of graphite by Acheson's process, the intermediate product is :

carborundum

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

diaspore

No worries! We‘ve got your back. Try BYJU‘S free classes today!

tincal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

dry ice

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A carborundum
$C c o k e + S i O_{2} \to S i O + C O$
$S i O_{2} + C O \to S i O + C O_{2}$
$C + C O_{2} \to 2 C O$
$C + S i O \to S i C + C O_{2}$
$S i C 3700 K \to S i v a p o u r s + C g r a p h i t e$
Thus, carborundum ( $S i C$ ) is formed as an intermediate product.

Suggest Corrections

Similar questions

O_{2}

H_{2} S O_{4}

N a_{2} C O_{3}

Join BYJU'S Learning Program