During the purification of copper by electrolysis:

the anode used is made of copper ore

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pure copper is deposited on the cathode

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the impurities such as

A g, A u

present in solution as ions

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concentration of

C u S O_{4}

solution remains constant during dissolution of

C u

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Solution

The correct options are
A pure copper is deposited on the cathode
C concentration of $C u S O_{4}$ solution remains constant during dissolution of $C u$
D the anode used is made of copper ore
Anode : - Impure copper or crude copper.
Cathode : Pure copper
Electrolyte : $15 %$ $C u S O_{4}$ solution $+ 5 %$ $H_{2} S O_{4}$
When electric current is passed through the electrolyte, the angle anode gradually dissolve and pure copper is deposited on the cathode which gradually grow in size. The impurities like, Fe,Zn,Ni, etc, dissolved in the solution as while gold, silver, platinum settle down the anode as anode mud.
Reaction Occurring are as follows.
$C u S O_{4} ⇌ C u^{+ 2} + S O_{4}^{- 2};$ At anode : $C u - 2 e \to C u^{+ 2}$
Cathode : $C u^{+ 2} + 2 e \to C u$

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Similar questions

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